2y^2+3(2y*y)=10

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Solution for 2y^2+3(2y*y)=10 equation:


Simplifying
2y2 + 3(2y * y) = 10

Multiply y * y
2y2 + 3(2y2) = 10

Remove parenthesis around (2y2)
2y2 + 3 * 2y2 = 10

Multiply 3 * 2
2y2 + 6y2 = 10

Combine like terms: 2y2 + 6y2 = 8y2
8y2 = 10

Solving
8y2 = 10

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '8'.
y2 = 1.25

Simplifying
y2 = 1.25

Take the square root of each side:
y = {-1.118033989, 1.118033989}

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